Reference solution
The shape we check against. Any implementation that passes the assertions is valid — this one favours clarity.
def sf_trips(df):
return df.loc[df['city'] == 'SF', ['trip_id', 'driver', 'fare']]
The DataFrame `trips` is preloaded. Write sf_trips(df) that returns trips where city == 'SF', keeping only trip_id, driver, and fare columns (in that order).
preloaded fixtures
import pandas as pd
import numpy as np
trips = pd.DataFrame({
"trip_id": [1, 2, 3, 4, 5, 6, 7, 8, 9, 10],
"driver": ["alex", "alex", "sam", "sam", "alex", "jordan", "jordan", "sam", "alex", "jordan"],
"city": ["SF", "SF", "NYC", "NYC", "SF", "LA", "LA", "NYC", "SF", "LA"],
"fare": [12.5, 8.0, 20.0, 15.0, 9.5, 18.0, 22.0, 11.0, 14.0, 16.5],
"surge": [1.0, 1.0, 1.5, 1.2, 1.0, 2.0, 1.5, 1.0, 1.3, 1.8],
"distance": [3.2, 2.1, 5.5, 4.0, 2.8, 6.0, 7.2, 3.5, 3.8, 5.0],
})
hint ladder
Inspect a chained expression (df.query(…).groupby(…).agg(…)) to see the shape and preview after each step.
Run your code to see its output, or check your solution to grade it.
Reference solution
The shape we check against. Any implementation that passes the assertions is valid — this one favours clarity.
def sf_trips(df):
return df.loc[df['city'] == 'SF', ['trip_id', 'driver', 'fare']]
Code is blurred until you solve this problem — the reasoning stays readable.