Word frequency counter

pythoneasydictsstrings

Write word_counts(text) that returns a dict mapping each lowercase word to how many times it appears. Split on whitespace.

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solution.py

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Reference solution

The shape we check against. Any implementation that passes the assertions is valid — this one favours clarity.

def word_counts(text):
    counts = {}
    for w in text.lower().split():
        counts[w] = counts.get(w, 0) + 1
    return counts

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